We can make it by a simple equation.
M1V1 = M2V2
Example 1 :
Theres a 40.0mL of 0.400M NaOH solution is diluted to a final volume of 200.0mL, calculate the new concentration.
Let x be the new concentration.
0.400 x 40.0/1000.0 = 100/1000x
x= 6.25
The new concentration is 6.25M
Example 2 :
A 0.700M solution is concentrated by evaporation to a reduced final volume of 200.0mL and a molarity of 1.65M. Calculate the original volume.
Let V be the original volume.
0.700V = 200/1000 x 1.65
V = 2.33
The original volume was 2.33L
The original volume was 2.33L
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